15x^2+43x=8

Solution for 15x^2+43x=8 equation:

15x^2+43x=8

We move all terms to the left:

15x^2+43x-(8)=0

a = 15; b = 43; c = -8;
Δ = b2-4ac
Δ = 432-4·15·(-8)
Δ = 2329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-\sqrt{2329}}{2*15}=\frac{-43-\sqrt{2329}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+\sqrt{2329}}{2*15}=\frac{-43+\sqrt{2329}}{30}
$